¡°·ÅÐÄ£¬ÀÏʦÔç×ÔϰûÀ´£¬ÎÒ²»»á¸æ×´µÄ¡£¡±
º£Ã÷ÔÂÕâô˵£¬ËýÕæµÄ²»»á¸æ×´µÄ£¬ËµµÄÍêÈ«ÊÇʵ»°£¬¹ËÖ®è¡È´¹´×Å´½½ÇЦÁËÆðÀ´¡£
Ëû±¾¾ÍÉúµÃºÃ¿´£¬²»Ð¦Ê±´ø×ÅЩÒõÓôµÄ°µºÚ¸Ð£¬Ð¦ÆðÀ´Ê±£¬ÒõÓô²»¼ûÁË£¬ÂúÂúµÄ¶¼ÊÇÈÃÈËÐ͝µÄÇåöÁÐãÑÅ¡£
Éú»îÔÄÀú»ù±¾ÎªÁãµÄº£Ã÷Ô¶ԹË֮衵ÄЦºÜ²»ÂúÒ⣬ËäÈ»ËûЦÆðÀ´ºÜºÃ¿´£¬¿ÉÊÇÒÀÈ»²»ÄÜÃÖ²¹Ëû¾ÓÈ»²»ÏàÐÅËýµÄʵ»°µÄ×ï¹ý¡£
½¿ºßÁËÒ»Éù£¬º£Ã÷ÔÂ×øÖ±ÁËÉíÌ壬²»ÔٹܹË֮衣¬Ò»±¾Õý¾µØ·×ÅÊÖÀïµÄÓïÎÄÊé¡£
·ÁËÒ»»á£¬º£Ã÷ÔÂÓÐЩ㣬¿Îºó£¬ÒªÇóдһƪ²»ÉÙÓÚÎå°Ù×ÖµÄÔĺó¸Ð¡£
ÎÄÖÐ×÷ÕßдµÀÍí°²£¬ÇëÎÊ×÷ÕßÕâ¾äÍí°²£¬ÔÚÎÄÖÐÆðµ½ÁËʲô×÷Ó㬱í´ïÁË×÷Õßµ±Ê±ÔõÑùµÄÒ»¸öÐľ³¡£
ʲô¹í£¿
´ÓСÉú»îÔÚÒ½Ôº£¬ÈÏ×Ö¿¿¼Ò½Ì£¬²»Óÿ¼ÊÔ²»ÓÃ×ö×÷Òµ£¬Ò²²»ÓÃÉÏѧµÄº£Ã÷Ô³¹µ×ã±ƣ¬ËýºöÈ»ÓÐÁËÒ»ÖÖ²»ÏéµÄÔ¤¸Ð¡£
Õâ¹ÉÔ¤¸ÐÈÃËýÌͳöÊé°ü£¬àèÀïžÀ²µØ·ÕÒÆðÁËÊé°üÀïµÄÊ飬·ÁËÒ»»á£¬º£Ã÷Ô¸ɴà°ÑÊéÈ«²¿µ¹ÔÚÁË×À×ÓÉÏ¡£
Ëýµ¹ÊéµÄ¶¯¾²Í¦´ó£¬²»ÉÙÃ÷Àï°µÀïÆäʵһֱÔÚ¹Ø×¢×ÅËýÕâ¸öλÖõÄÄÐÉúÅ®Éú·×·×¿´Á˹ýÀ´¡£
ÆäÖУ¬ÄÐÉú¹Ø×¢ËýÊÇÒòΪËýºÃ¿´£¬ÊÇËûÃÇÐÄÀïµÄÅ®Éñ£¬Å®ÉúÔòÊÇ´ó¶àÒòΪ¹Ë֮衡£
ÓïÎÄ¡¢Êýѧ¡¢ÎïÀí¡¢»¯Ñ§¡¢Ó¢Óï¡¢ÀúÊ·¡¢µØÀí¡¢ÕþÖΡ¡µÈµÈµÈµÈ¡£
»¹Óи÷¿Æ¶ÔÓ¦µÄÊÔ¾í£¬Ï°Ìâ²á¡£
·¿ªÊýѧϰÌâ²á£¬ÉÏÃæ¸÷ÖÖ×Ö·ûºÍÊý×Ö×é³ÉµÄÌâÄ¿£¬²ð¿ªÁËËýÿ¸ö×Ö¶¼ÈÏʶ£¬ºÏÔÚÒ»ÆðÍðÈçÔÚ¿´ÌìÊé¡£
·¿ª»¯Ñ§ÊÔ¾í£ºÏÂÁйØÓÚÈÈ»¯Ñ§·´Ó¦µÄÃèÊö£¬ÕýÈ·µÄÊÇ£º ( )
a.hclºÍnaoh·´Ó¦µÄÖкÍÈȦ¤h£½£57.3 kj/mol£¬Ôòh2so4ºÍba(oh)2·´Ó¦µÄÖкÍÈȦ¤h£½2x(£57.3)kj/mol
b.co(g)µÄȼÉÕÈÈÊÇ283.0 kj/mol£¬Ôò2co2(g)===2co(g)£«o2(g)·´Ó¦µÄ¦¤h£½£«2x283.0 kj/mol
c.ÐèÒª¼ÓÈȲÅÄÜ·¢ÉúµÄ·´Ó¦Ò»¶¨ÊÇÎüÈÈ·´Ó¦
d.1 mol¼×ÍéȼÉÕÉú³ÉÆøÌ¬Ë®ºÍ¶þÑõ»¯Ì¼Ëù·Å³öµÄÈÈÁ¿ÊǼ×ÍéµÄȼÉÕÈÈ
ÑÛǰȫÊÇ×Ö·ûÔÚ·ÉÎ裬º£Ã÷Ô¼«Ð¡ÉùµØàÓÁËÒ»Éù£¬ÏñÊÇÈíÃȵÄèßäÓ×áÌÔÚºßßóÒ»Ñù£¬¿É°®µÃÈÃÈËÐͼ¿ì»¯ÁË¡£
ºÃÔÚËýÉùÒô¼«Ð¡£¬Ö»ÊDZ»Í¬×À¹ËÖ®è¡Ìýµ½Á˶øÒÑ¡£
ϵͳ£¬Îҿɲ»¿ÉÒÔ²»ÉÏѧ£¿
¡¾¶££¬²»¿ÉÒÔŶ£¬ËÞÖ÷°¡£¬È˰¡²»ÄÜÒòΪÓÐÁ˽ðÊÖÖ¸¾Í·ÅÆúѧϰ˼¿¼ÁËѽ£¬ËäÈ»ÎÒÇÀµ½µÄ½ðÊÖÖ¸ºÜÇ¿´ó£¬¿ÉÊÇ£¬ÄãÒ²Òª¶àѧϰ¶à˼¿¼£¬×öÒ»¸ö²»Ö¹Íâ±íÃÀÀö£¬ÄÚºÒ²¼«Îª·á¸»ÓÐȤµÄÆæÅ®×Óѽ¡£¡¿
0005×÷Õß¾«·ÖÁË(1/2),µã»÷ÏÂÒ»Ò³¼ÌÐøÔĶÁ